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已知等差数列{an}的前n项和伟sn,公差d≠0,且s3+s5=50,a1,a4,a13城等比数列.求数
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解答
已知等差数列{an}的前n项和伟sn,公差d≠0,且s3+s5=50,a1,a4,a13城等比数列.求数{an}通项.Sn=a1*n+[n(n-1)d]/2 S3=3a1+[3(3-1)d]/2 =3a1+3dS5=5a1+[5(5-1)d]/2 =5a1+10d因为 s3+s5=50所以 3a1+3d + 5a1+10d=50即:8a1...
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