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设函数f(x)=acos(2x+π/3)+a/2+b的定义域为[-π/3,π/6],值域为[-1,5]
人气:384 ℃ 时间:2019-11-05 04:08:47
解答
∵x∈[-π/3,π/6] ∴2x+π/3∈[-π/3,2π/3]
∴cos(2x+π/3)∈[-1/2,1]
∵f(x)值域为[-1,5]
当a>0时,
cos(2x+π/3)=1时,f(x)max=3a/2+b=5
cos(2x+π/3)=-1/2时,f(x)min=b=-1
∴a=4,b=-1
当a
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