2-(3x-5)/(x²+2x-3)>=0
(2x²+4x-6-3x+5)/(x²+2x-3)≥0
(2x-1)(x+1)/(x+3)(x-1)≥0
即(2x-1)(x+1)(x+3)(x-1)≥0
零点是-3,-1,1/2,1
分母不等于0
所以x1