解
(2a+1)²-2a(2a-1)
=4a²+4a+1-4a²+2a
=6a+1
=6×(1/2)+1
=3+1
=4
(3a-1)²-(2a+1)(2a-1)
=9a²-6a+1-4a²+1
=5a²-6a+2
=5×(1/4)-6×1/2+2
=5/4-3+2
=5/4-4/4
=1/4