若a1=1-1/m,a2=1-1/a1,a3=1-1/a2.则a2012的值为多少 用含有m的代数式表示
人气:155 ℃ 时间:2019-10-26 06:47:39
解答
an+3=1-1/an+2=1-1/(1-1/an+1)=1-1/(1-1/(1-1/an))=1-1/(1-an/(an - 1))=1+an - 1=an
3个一循环a2012=a(3*670…2)=a2=1-1/a1
=1/(1-m)
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