由题意可知,x＞0,可设x=a+b,其中a∈N,0≤b＜1,[2X]+[3X]=2a+3a+[2b]+[3b]=5a+[2b]+[3b]=95.0≤[2b]≤1,0≤[3b]≤2,0≤[2b]+[3b]≤3.{[2b]+[3b]}为正整数且含有因数5,所以{[2b]+[3b]}=0,立即可得a=19,从而x=19+b,即19...