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数学
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求y=x2+3x-1/x+1导数
人气:470 ℃ 时间:2020-05-21 23:16:24
解答
y=(x^2+3x-1)/(x+1)
=(x^2+2x+1+x+1-3)/(x+1)
=x+1+1-3/(x+1)
=x+2-3/(x+1)
y'=1+3/(x+1)^2
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