> 数学 >
dy/dx=y(y-1),y(0)=0的特解
人气:471 ℃ 时间:2020-03-19 04:56:17
解答
dy/dx=y(y-1)
(1/(y-1)-1/y)dy = dx
ln|(y-1)/y| = x+ C
y(0) =0
C=0
ln|(y-1)/y| = x
(y-1)/y = e^x
y(1-e^x) = 1
y = 1/(1-e^x)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版