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两道三角恒等变换题目(需要解释)
一.(1/sin10°)-(根号3/sin80°)=
二.若tanα=1/3,则cos2α=
人气:423 ℃ 时间:2020-10-01 21:31:12
解答
1/sin10°-√3/sin80°=1/sin10°-√3/cos10° =(cos10°-√3sin10°)/sin10°cos10° =2(1/2cos10°-√3/2*sin10°)/sin10°cos10° =2cos(10°+60°)/sin10°cos10° =4cos70°/sin20° =4sin20° /sin20° =4tan...
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