1/(m^2-m)+(m-5)/(2m^2-2) =1/[m(m-1)]+(m-5)/[2(m+1)(m-1)]=2(m+1)/[2m(m+1)(m-1)]+m(m-5)/[2m(m+1)(m-1)]=[2(m+1)+m(m-5)]/[2m(m+1)(m-1)]=(m²-3m+2)/[2m(m+1)(m-1)]=(m-1)(m-2)/[2m(m+1)(m-1)]=(m-2)/[2m(m+...