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求通解dy/dx=sin(x-y)
人气:371 ℃ 时间:2020-03-21 18:27:52
解答
∵dy/dx=sin(x-y)==>dy=sin(x-y)dx==>dx-dy=dx-sin(x-y)dx==>d(x-y)=(1-sin(x-y))dx==>d(x-y)/(1-sin(x-y))=dx==>d(x-y)/(sin((x-y)/2)-cos((x-y)/2))^2=dx (应用(sin((x-y)/2)^2+(cos((x-y)/2)^2=1)==>(sec((x-y)/2...追问
这个您可以做吗?(3xy+2y^2+y)dx+(x^2+2xy+x+2y)dy=0求方程的一个积分因子>此方程的积分因子是1/√(xy+y^2)。
∵(3xy+2y^2+y)dx+(x^2+2xy+x+2y)dy=0
==>(3xy+2y^2)dx+(x^2+2xy)dy+ydx+xdy+2ydy=0
==>(3xy+2y^2)dx+(x^2+2xy)dy+d(xy+y^2)=0
==>[(3xy+2y^2)dx+(x^2+2xy)dy]/√(xy+y^2)+d(xy+y^2)/√(xy+y^2)=0(等式两端同乘1/√(xy+y^2))
==>2d[x√(xy+y^2)]+2d[√(xy+y^2)]=0
==>x√(xy+y^2)+√(xy+y^2)=C(C是常数)
==>(x+1)√(xy+y^2)=C
∴原方程的通解是(x+1)√(xy+y^2)=C。谢谢了
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