函数y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)是偶函数还是奇函数?_数学解答

函数y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)是偶函数还是奇函数?

人气：428 ℃　时间：2019-11-08 15:05:37

解答

f(x)=y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)f(-x)=[2^(-x)-1]/[2^(-x)+1]+ln(-x-1)/(-x+1)[2^(-x)-1]/[2^(-x)+1]上下同乘2^x=(1-2^x)/(1+2^x)=-(2^x-1)/(2^x+1)ln(-x-1)/(-x+1)=ln[-(x+1)/-(x-1)]=ln(x+1)/(x-1)=ln{1/[...