求函数y=cos²x-cosx+2的单调递减区间与单调递增区间解析：∵f(x)=(cosx)^2-cosx+2令f’(x)=-2(cosx)sinx+sinx=sinx(1-2cosx)=0Sinx=0==>x1=2kπ,x2=2kπ+π1-2cosx=0==>x3=2kπ-π/3,x4=2kπ+π/3∵f’’(x)=-2...