求三元一次方程组的解有过程 x-y-z=1 3x+5y+7z=11 4x-y+2z=-1
人气:123 ℃ 时间:2019-11-14 01:36:35
解答
x-y-z=1 ①
3x+5y+7z=11 ②
4x-y+2z=-1 ③
①乘5得
5x-5y-5z=5 ④
由④加②得
4x+z=8 ⑤
③减①得
3x+3z=-2 ⑥
由⑤乘3再减⑥得
9x=26
x=26/9代入⑥得
z=-32/9
由x,z可得
y=49/9
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