可设该实根为m,(m∈R),则m²+zm+4+3i=0.易知,m≠0.方程两边同除以m,可化为-z=[m+(4/m)]+(3/m)i.===>|z|²=[m+(4/m)]²+(3/m)²=8+[m²+(25/m²)]≥8+10=18.===>|z|²≥18.===>|z|≥3√2.===>|z|min=3√2.