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〔5xy^2(x^2-3xy)-(-3x^2y^3)〕/2x^2y^2
人气:280 ℃ 时间:2020-01-09 06:44:40
解答
〔5xy^2(x^2-3xy)-(-3x^2y^3)〕/2x^2y^2=(5x³y² - 15x²y³+3x²y³)/(2x^2y^2)=(5x³y² - 12x²y³)/(2x^2y^2)=(5xy-12y)/2=(5xy/2) - 6y
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