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已知tanx=3,计算(4sinx-2cosx)/(5cosx+3sinx)的值
人气:121 ℃ 时间:2020-01-27 22:15:33
解答
tanx=sinx/cosx=3则 cosx,sinx均不为零,
所以(4sinx-2cosx)/(5cosx+3sinx)
=(4sinx/cosx-2)/(5+3sinx/cosx)
=(4tanx-2)/(5+3tanx)
=(4*3-2)/(5+3*3)
=10/14
=5/7
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