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计算:(1/9a^2+6a+1-1/3a+1)/a^2/3a^2+a
人气:167 ℃ 时间:2020-05-27 09:52:16
解答
=(1/(3a+1)^2-1/(3a+1))/(a^2/3a^2+a)
=(3a/(3a+1)^2)/(a^2/3a^2+a)
=(3a/(3a+1)^2)/(a/(3a+1))
=3/(3a+1)
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