设A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²+3x-y 若|x-2a|+(y+3)²=0,且B-2A=a,求A的值
人气:435 ℃ 时间:2019-08-18 07:10:05
解答
由|x-2a|+(y+3)²=0得:x=2a,y=-3,
B-A=(4x²-6xy+2y²+3x-y)-2(2x²-3xy+y²-x+2y)
=5X-5Y
∴10a+15=a
9a=-15
a=-5/3.那A咧??我求大A不是小a........X=-10/3,y=-3A=2x²-3xy+y²-x+2y=2(-10/3)^2-3(-10/3)*(-3)+(-3)^2-(-10/3)+2(-3)=200/9-30+9+10/3-6=230/9-27=-13/9
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