当x=-6/5时,(1+2/x-1)^3*(1-3/x-2)^2除以(x-2)^2*(x-1)^2分之（x-5)^2*(x+1)^2=(x+1/x-1)^3*(x-5/x-2)^2(x-2)^2*(x-1)^2除以（x-5)^2*(x+1)^2=(x+1/x-1)(1/x-2)^2*(x-2)^2=(x+1/x-1)=(-1/5)/(-11/5)=1/11