1分析零点.
令2x+1=0 得x=-1/2
令3x-2=0 得x=2/3
2 分情况讨论
ax<=-1/2 l2x+1l=-2x-1 ;l3x-2l=2-3x
l2x+1l+l3x-2l=-2x-1+2-3x=-5x+1≥5 x<=-4/5(满足x<=-1/2)
b-1/2l2x+1l+l3x-2l=2x+1+2-3x=-x+3≥5 x<=-2(不满足-1/2cx>=2/3 l2x+1l=2x+1 ;l3x-2l=3x-2
l2x+1l+l3x-2l=2x+1+3x-2=5x-1≥5 x>=6/5(满足x>=2/3)
总结 不等式解集｛x|x<=-4/5或x>=6/5｝