m=1 mn=2 1/mn+1/(n+1)(m+1)+1/(n+2)(m+2)+1/(n+3)(m+3)...+1/(n+2010_数学解答

m=1 mn=2
1/mn+1/(n+1)(m+1)+1/(n+2)(m+2)+1/(n+3)(m+3)...+1/(n+2010)(m+2010)
=多少?

人气：496 ℃　时间：2020-05-09 03:22:13

解答

因为:m=1 mn=2,所以:m=1 n=2/m=2,把m=1,n=2代入下面式子中,便可得解.即为:1/1*2+1/(2*3)+1/(3*4)...+1/(2011*2012)发现没有1/2=1/1-1/21/(2*3)=1/2-1/3 1/(3*4)=1/3-1/4依此类推,1/(2011*2012)=1/2011-1/2022所以原...