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已知1/x-1/y=3,求(2x-3xy-2y)/(x-2xy-y)
人气:429 ℃ 时间:2020-05-10 16:27:15
解答
1/x-1/y=3
∴(y-x)/xy=3,即y-x=3xy
∴x-y=-3xy
∴(2x-3xy-2y)/(x-2xy-y)
=[2(x-y)-3xy]/[(x-y)-2xy]
=(-6xy-3xy)/(-3xy-2xy)
=9/5
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