√x+√(y-1)+√(z-2)=(x+y+z)/2.2√x+2√(y-1)+√2(z-2)-x-y-z=0x+y+z-2√x-2√(y-1)-√2(z-2)=0(x-2√x+1)+[(y-1)-2√(y-1)+1]+[(z-2)-2√(z-2)+1]=0.(√x-1)²+[√(y-1)-1]²+[√(z-2)-1]²=0.x-1=0,y...