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sin a=1/3 则sin 3a=?
人气:436 ℃ 时间:2020-09-05 20:47:15
解答
sin(3a)=sin(2a+a)
=sin(2a)cosa+cos(2a)sina
=2sinacosacosa+[1-2(sina)^2]sina
=2sina[1-(sina)^2]+sina-2(sina)^3
=2sina-2(sina)^3+sina-2(sina)^3
=3sina-4(sina)^3
=3(1/3)-4(1/3)^3
=1-4/27
=23/27
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