已知A=x^2-xy-y^2,B=3xy+x^2.x,y满足条件(x-3)^2+(y+2)^2=0求1/2[2(A-B)-3A+1/3[3(A+2B)-3A]-1/2A
完整
人气:416 ℃ 时间:2020-04-13 05:20:15
解答
(x-3)^2+(y+2)^2=0(x-3)^2=0,(y+2)^2=0x=3y=-21/2[2(A-B)-3A+1/3[3(A+2B)-3A]-1/2A=1/2[(A-B)-3A+A+2B-3A]-1/2A=1/2[A-B-3A+A+2B-3A]-1/2A=1/2[A-3A+A-3A-B+2B]-1/2A=1/2[-4a+B]-1/2A=-2A+1/2B-1/2A=-5/2A+1/2B=-5...
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