(1)6+3*(1/6)=6.5(2)x^2+x+3=7 =>-2x^2-2x-3=-11(3)ax^5+bx^3+cx+b=10,x=2=>32a+8b+2c+b=10 =>-32a-8b-2c=b-10当x=-2时原式=-32-8b-2c+b=2b-10当x=0时得到b=10所以-32-8b-2c+b=2b-10=10已知a-b/a+b=4求5a+5b/a-b/2a+2b的值确定题目没错么？