课堂上,老师给大家出了这样一道题:“已知5a-2x+3=0,4b-7x-21=0,求X的取值范围
人气:197 ℃ 时间:2020-03-25 08:44:03
解答
毛线哦,明明是取值范围答案: 5a-2x+3+0 a=2x-3\5 4b-7x-21=0 b=21+7x/4 因为a<6≤b所以2x-3/5<6≤21+7x/4 所以3/7< x ≤16.5
记得采纳啊
推荐
- 课堂上,老师给大家出了这样一道题:"已知5a-2x+3=0,4b-7x-21=0
- 课堂上老师给大家出了一道这样的题目,已知5a-2x+3=0
- 1.已知1※3=1*2*3,4※5=4*5*6*7*8,请计算3※4分之6※4 2.若A△B=5A-4B,已知X△(5△2)=12,求X
- 已知A={x|x^2-7x+6≤0},若B={x|x^2-2ax+5a≤0,a∈R},且A∩B=B,求a的取值范围.急!
- (5a-4b)^2-(5a-4b)(3a-2b) (2x-1)(2x+1)(4x^2-1)
- He doesn't suppose that you'll come in time,_______?A does he B,will you
- Tom()(be)ill last week,he()(be)much better now.用所给词的适当形式填空.
- Which month has 28 days?
猜你喜欢