y=(3x+2)/(2x-1)
y(2x-1)=3x+2
2xy-y=3x+2
(2xy-3x)=y+2
(2y-3)x=y+2
x=(y+2)/(2y-3)
所以,2y-3不=0,即Y不=3/2
即值域是(-无穷,3/2)U(3/2,+无穷)