> 数学 >
对数指数运算问题
(1/27)^2+lg2*lg2500+2(lg5)^2+9^(2+log93)=
人气:216 ℃ 时间:2020-01-30 02:03:08
解答
原式=(1/27)^2+lg2*lg(5^2*10^2)+2(lg5)^2+9^2*9^log93
=(1/27)^2+lg2*(2lg5+2)+2(lg5)^2+81*3
=(1/27)^2+2lg2*lg5+2lg2+2(lg5)^2+81*3
=(1/27)^2+2(lg2+lg5)*lg5+2lg2+81*3
=(1/27)^2+2lg5+2lg2+81*3
=(1/27)^2+2+81*3
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版