设A（1+1/3）*（1+1/5）*（1+1/7）*.*（1+1/2N-1)=4/3*6/5.2n/2n-1B=5/4*7/6.2n+1/2n则A*B=2n+1/3∵2n/2n-1>2n+1'2n∴A>B,A^2>AB∴A^2>2n+1/3>2n+1/4>2n-1/4∴A>根号2N-1/4即(1+1/3）*（1+1/5）*（1+1/7）*.*（1+1/2...