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arccosx=5π/6,则arctan(2x/3)
人气:153 ℃ 时间:2020-06-21 21:07:50
解答
cos5π/6=-cosπ/6=-根号3/2
arccosx=5π/6
X=-根号3/2
arctan(2x/3)
=arctan(-根号3/2*2/3)
=arctan(-根号3/3)
tan5π/6=-根号3/3
arctan(2x/3)=5π/6
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