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计算:(1)-(-4²的绝对值)÷3分之1×3×(-1)³
(2)-2分之3÷[-2²×(-2分之3)²-(-2)³+(-2005)的十次方×0]
(1)-(-4²的绝对值)÷3分之1×3×(-1)-(-1)³
人气:298 ℃ 时间:2020-05-02 14:18:19
解答
计算:
(1)-(-4²的绝对值)÷3分之1×3×(-1)-(-1)³
=-16 x 3 x 3 x (-1) - (-1)
= 144 +1
= 145
(2)-2分之3÷[-2²×(-2分之3)²-(-2)³+(-2005)的十次方×0]
= -3/2 ÷ [ -4 x 9/4 - (-8) ]
= -3/2 ÷ [ -4 x 9/4+8 ]
= -3/2 ÷ [ -9 +8]
= -3/2 ÷ (-1)
= 2分之3
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