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(xx-yy-zz)(xx-yy-zz)-4yyzz因式分解
人气:462 ℃ 时间:2020-06-17 02:41:17
解答
(xx-yy-zz)(xx-yy-zz)-4yyzz
=(x^2-y^2-z^2)^2-(2yz)^2
=(x^2-y^2-z^2+2yz)(x^2-y^2-z^2-2yz)
=[x^2-(y-z)^2][x^2-(y+z)^2]
=(x+y-z)(x-y+z)(x-y-z)(x+y+z)
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