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如何计算啊.(log底数4真数3+log底数8真数3)乘(log底数3真数2+log底数9真数2)=?
人气:484 ℃ 时间:2019-08-21 14:13:55
解答
(log4 3 +log8 3 )*(log3 2 +log9 2 )
=((1/2)*log2 3+(1/3)*log2 3)*(log3 2+(1/3)*log3 2)
=(5/6)log2 3 *(4/3)log3 2
=(5/6)*(4/3)
=10/9
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