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计算:1.【a- a+1分之a】÷ a²-4分之a³-2a² 2.a²-b²分之1÷【a+b分之1 +
计算:1.【a- a+1分之a】÷ a²-4分之a³-2a²
2.a²-b²分之1÷【a+b分之1 + a-b分之1】
人气:288 ℃ 时间:2020-05-07 03:25:52
解答
[a-a/(a+1)]÷[(a^3-2a^2)/(a^2-4)]
=[a(a+1)/(a+1)-a/(a+1)]÷[a^2(a-2)/(a-2)(a+2)]
=[(a^2+a-a)/(a+1)]÷a^2/(a+2)
=a^2/(a+1)÷a^2/(a+2)
=a^2/(a+1)*(a+2)/a^2
=(a+2)/(a+1)
1/(a^2-b^2)÷[1/(a+b)+1/(a-b)]
=1/(a^2-b^2)÷[(a-b)/(a-b)(a+b)+(a+b)/(a-b)(a+b)]
=1/(a^2-b^2)÷[(a-b)/(a^2-b^2)+(a+b)/(a^2-b^2)]
=1/(a^2-b^2)÷[(a-b+a+b)/(a^2-b^2)]
=1/(a^2-b^2)÷[2a/(a^2-b^2)]
=1/(a^2-b^2)*(a^2-b^2)/(2a)
=1/(2a)
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