(x+1)/3-(y+2)/4=0 (x-3)/4-(y-3)/3=1/12是不是这样?4*（x+1）-3(y+2)=03(x-3)-4(y-3)=14x+4-3y-6=03x-9-4y+12-1=04x-3y-2=03x-4y+2=012x-9y-6=012x-16y+8=0-9y-6+16y-8=07y=14y=24x-3y-2=04x=2+3y=2+6x=2回答完毕!...