f(x)=mx²-(3m+1)x+2(m+1)=mx²-(2m+ m+1)x+2(m+1)=[mx-(m+1)]*(x-2)则不等式f(x)>0可写为：[mx-(m+1)]*(x-2)>0（1）当m=-½时,有：(-½*x - ½)*(x-2)>0,即(x+1)(x-2)0,此时解得：x≠2；（b）...