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已知xy^2=-2求xy(2x^3y^7+5x^2y^5-y)的值
人气:168 ℃ 时间:2019-10-18 02:30:35
解答
xy(2x^3y^7+5x^2y^5-y)
=xy[2y(xy^2)^3+5y(xy^2)^2-y]
=xy[2y(-2)^3+5y(-2)^2-y]
=xy(-16y+20y-y)
=3xy^2
=3*(-2)
=-6
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