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设z=sin²(x+y),求所有的二阶偏导数
人气:475 ℃ 时间:2020-07-03 21:26:09
解答
dz/dx=2sin(x+y)*cos(x+y) dz/dy=2sin(x+y)*cos(x+y)
d(dz/dx)/dx=2cos(x+y)*cos(x+y)-2sin(x+y)*sin(x+y)
d(dz/dy)/dy=2cos(x+y)*cos(x+y)-2sin(x+y)*sin(x+y)
d(dz/dx)/dy=2cos(x+y)*cos(x+y)-2sin(x+y)*sin(x+y)
没错,三个一样...
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