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(x-2)(x+2)-(x-2)(x+2)-(x-1)(x+3)-(x+2)还有(2x+3y-2)(2x-3y+2)
还有已知xy²=-2 求xy(2x³y^7-5x²y^5-y)
坐等
我搞错了(x-2)(x+2)-(x-1)(x+3)-(x+2)²
人气:427 ℃ 时间:2020-04-10 07:29:39
解答
(x-2)(x+2)-(x-2)(x+2)-(x-1)(x+3)-(x+2)=-(x-1)(x+3)-(x+2)=-x²-2x+3-x-2=-x²-3x+1(2x+3y-2)(2x-3y+2) =[2x+(3y-2)][2x-(3y-2)]=4x²-(3y-2)²=4x²-9y²+12y-4xy(2x³y^7-5x²...
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