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d/dx sin^8(cos(4x))
人气:179 ℃ 时间:2020-05-19 17:02:05
解答
d/dx sin^8(cos(4x))=8sin^7(cos(4x) dsin(cos(4x)/dx=8sin^7(cos(4x)*cos(cos(4x)) dcos(4x)/dx=8sin^7(cos(4x)*cos(cos(4x))*(-sin(4x)) d(4x)/dx=-32sin^7(cos(4x)*cos(cos(4x))*sin(4x)
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