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1:计算 (2+1)*(2^2+1)*(2^4+1)*(2^8+1)+1 结果等于?
2:分解因式 X^2 - 10X + 16
人气:418 ℃ 时间:2020-03-24 09:01:34
解答
1.(2+1)*(2^2+1)*(2^4+1)*(2^8+1)+1
=(2-1)(2+1)*(2^2+1)*(2^4+1)*(2^8+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)+1
=(2^4-1)(2^4+1)(2^8+1)+1
=(2^8-1)(2^8+1)+1
=2^16-1+1
=2^16
2.X^2 - 10X + 16 =(X-2)(X-8)
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