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数学
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计算(-x^2y^3 z)^4÷(-x^2y^3 z)^2
以及:(-x-y)^4÷(x+y)^3
b·(-b)^2+(-b)·(-b)^2
(-a^3)^2·(-a^2)^3
(-x)·x^5·(-x)^2·x^6
人气:265 ℃ 时间:2020-05-16 18:26:36
解答
(-x^2y^3 z)^4÷(-x^2y^3 z)^2
=x^8y^12z^4÷x^4y^6z^2
=x^4y^6z^2
(-x-y)^4÷(x+y)^3
=(x+y)^4÷(x+y)^3
=x+y
b·(-b)^2+(-b)·(-b)^2
=b^3-b^3
=0
(-a^3)^2·(-a^2)^3
=a^6x(-a^6)
=-a^12
(-x)·x^5·(-x)^2·x^6
=-x^6*x^2*x^6
=-x^14
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