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x=(1-t^2)/1+t^2
y=2t/1+t^2
(t为参数)
x=t^2-2t
y=t^2+2
(t为参数~)
求救啊!
人气:458 ℃ 时间:2020-04-06 10:35:59
解答
x=(1-t^2)/1+t^2 x^2=(1-2t^2+t^4)/(1+t^2)^2y=2t/1+t^2 y^2=4y^2/(1+t^2)^2x^2+y^2=[(1-2t^2+t^4)+4t^2]/(1+t^2)^2=(1+2t^2+t^4)/(1+t^2)^2=(1+t^2)^2/(1+t^2)^2=1x^2+y^2=1单位圆x=t^2-2t y=t^2+2y-x=2+2tt=(y-x-2...
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