若tanα=3,求sin²α-sinα×cosα﹢2×cos²α
人气:356 ℃ 时间:2020-04-03 11:17:02
解答
tanα=3
(sin²α-sinα×cosα﹢2×cos²α)/(sin²α+cos²α)
分子分母同时除以cos²a得
(tan²a-tana+2)/(tan²a+1)
=(9-3+2)/(9+1)
=8/10
=4/5
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