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求y等于cos^2(2x-π/3)的导数.
人气:180 ℃ 时间:2020-02-03 23:59:31
解答
y=cos²(2x-π/3)
=[cos(4x-2π/3)+1]/2
=(1/2)cos(4x-2π/3)+1/2
y'=-(1/2)sin(4x-2π/3)*4
=-2sin(4x-2π/3)
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