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[(a+b)²(a-b)²-3b²+3a²]÷(a²-b²)+1求化简,
人气:297 ℃ 时间:2020-02-05 10:49:35
解答
[(a+b)²(a-b)²-3b²+3a²]÷(a²-b²)+1
=[(a²-b²)²-3(a²-b²)]÷(a²-b²)+1
=a²-b²-3+1
=a²-b²-2
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