1/16(2x-1)(2x+1)(4x的平方+1)(x的4次方+1/16)
=(1/16)(4x²-1)(4x²+1)(16x^4+1)/16
=(1/256)(16x^4-1)(16x^4+1)
=(1/256)(256x^8-1)
=x^8-(1/256)