100mlPH=1的H2SO4溶液与100MLPH=13的NAOH混合后,求溶液的PH
人气：368 ℃ 时间：2019-10-17 06:14:20
解答
pH=1,说明氢离子浓度=0.1mol/L
pH=13,说明氢氧根离子浓度=0.1mol/L
两者体积相同,所以混合后pH=7
再罗嗦一句：是pH,不是PH...碰到我这样龟毛的老师会扣分的...
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